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342014433 = 3114004811
BaseRepresentation
bin10100011000101…
…011100111100001
3212211120010121020
4110120223213201
51200023430213
653534320053
711322034425
oct2430534741
9784503536
10342014433
11166070562
1296659029
1355b1b507
14335ccb85
152005c923
hex1462b9e1

342014433 has 4 divisors (see below), whose sum is σ = 456019248. Its totient is φ = 228009620.

The previous prime is 342014399. The next prime is 342014437. The reversal of 342014433 is 334410243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 342014433 - 217 = 341883361 is a prime.

It is a super-2 number, since 2×3420144332 = 233947744760622978, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (342014437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57002403 + ... + 57002408.

It is an arithmetic number, because the mean of its divisors is an integer number (114004812).

Almost surely, 2342014433 is an apocalyptic number.

It is an amenable number.

342014433 is a deficient number, since it is larger than the sum of its proper divisors (114004815).

342014433 is a wasteful number, since it uses less digits than its factorization.

342014433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114004814.

The product of its (nonzero) digits is 3456, while the sum is 24.

The square root of 342014433 is about 18493.6322284185. The cubic root of 342014433 is about 699.3289030769.

Adding to 342014433 its reverse (334410243), we get a palindrome (676424676).

The spelling of 342014433 in words is "three hundred forty-two million, fourteen thousand, four hundred thirty-three".

Divisors: 1 3 114004811 342014433