Base | Representation |
---|---|
bin | 110001110010000100110… |
… | …100110111110010010001 |
3 | 110010001020221020020102021 |
4 | 301302010310313302101 |
5 | 422022223214420423 |
6 | 11135332423051441 |
7 | 502106060531464 |
oct | 61620464676221 |
9 | 13101227206367 |
10 | 3421022420113 |
11 | 10a9935a744a1 |
12 | 4730255a0b81 |
13 | 1ba7a7602b8c |
14 | bb8150872db |
15 | 5dec6a1795d |
hex | 31c84d37c91 |
3421022420113 has 2 divisors, whose sum is σ = 3421022420114. Its totient is φ = 3421022420112.
The previous prime is 3421022420003. The next prime is 3421022420173. The reversal of 3421022420113 is 3110242201243.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2984957656209 + 436064763904 = 1727703^2 + 660352^2 .
It is a cyclic number.
It is not a de Polignac number, because 3421022420113 - 233 = 3412432485521 is a prime.
It is a super-3 number, since 3×34210224201133 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (3421022420173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1710511210056 + 1710511210057.
It is an arithmetic number, because the mean of its divisors is an integer number (1710511210057).
Almost surely, 23421022420113 is an apocalyptic number.
It is an amenable number.
3421022420113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3421022420113 is an equidigital number, since it uses as much as digits as its factorization.
3421022420113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3421022420113 its reverse (3110242201243), we get a palindrome (6531264621356).
The spelling of 3421022420113 in words is "three trillion, four hundred twenty-one billion, twenty-two million, four hundred twenty thousand, one hundred thirteen".
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