Base | Representation |
---|---|
bin | 110001110010010001011… |
… | …110011100010110110011 |
3 | 110010001210201120100102011 |
4 | 301302101132130112303 |
5 | 422023142032110103 |
6 | 11135405443503351 |
7 | 502114245441262 |
oct | 61622136342663 |
9 | 13101721510364 |
10 | 3421234644403 |
11 | 10a9a34846774 |
12 | 473084687b57 |
13 | 1ba80c57a294 |
14 | bb83532c5d9 |
15 | 5deda488d6d |
hex | 31c9179c5b3 |
3421234644403 has 4 divisors (see below), whose sum is σ = 3435918055128. Its totient is φ = 3406551233680.
The previous prime is 3421234644391. The next prime is 3421234644467. The reversal of 3421234644403 is 3044464321243.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3421234644403 - 25 = 3421234644371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3421234644103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7341705013 + ... + 7341705478.
It is an arithmetic number, because the mean of its divisors is an integer number (858979513782).
Almost surely, 23421234644403 is an apocalyptic number.
3421234644403 is a deficient number, since it is larger than the sum of its proper divisors (14683410725).
3421234644403 is a wasteful number, since it uses less digits than its factorization.
3421234644403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14683410724.
The product of its (nonzero) digits is 663552, while the sum is 40.
Adding to 3421234644403 its reverse (3044464321243), we get a palindrome (6465698965646).
The spelling of 3421234644403 in words is "three trillion, four hundred twenty-one billion, two hundred thirty-four million, six hundred forty-four thousand, four hundred three".
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