Base | Representation |
---|---|
bin | 110001110010011101010… |
… | …011001010001100001011 |
3 | 110010002022112211111222100 |
4 | 301302131103022030023 |
5 | 422024043322404003 |
6 | 11135441251324443 |
7 | 502122204522345 |
oct | 61623523121413 |
9 | 13102275744870 |
10 | 3421433013003 |
11 | 10aa026814a65 |
12 | 47311abb0723 |
13 | 1ba8416b2b55 |
14 | bb853808295 |
15 | 5deecabeba3 |
hex | 31c9d4ca30b |
3421433013003 has 24 divisors (see below), whose sum is σ = 5329061272080. Its totient is φ = 2108200055040.
The previous prime is 3421433012999. The next prime is 3421433013023. The reversal of 3421433013003 is 3003103341243.
3421433013003 is a `hidden beast` number, since 3 + 4 + 21 + 4 + 330 + 1 + 300 + 3 = 666.
It is not a de Polignac number, because 3421433013003 - 22 = 3421433012999 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3421433013023) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 243997626 + ... + 244011647.
It is an arithmetic number, because the mean of its divisors is an integer number (222044219670).
Almost surely, 23421433013003 is an apocalyptic number.
3421433013003 is a deficient number, since it is larger than the sum of its proper divisors (1907628259077).
3421433013003 is a wasteful number, since it uses less digits than its factorization.
3421433013003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 488009339 (or 488009336 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 27.
Adding to 3421433013003 its reverse (3003103341243), we get a palindrome (6424536354246).
The spelling of 3421433013003 in words is "three trillion, four hundred twenty-one billion, four hundred thirty-three million, thirteen thousand, three".
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