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3422614125113 = 4271801361303
BaseRepresentation
bin110001110011100011101…
…100101111101000111001
3110010012100212022020012022
4301303203230233220321
5422034003204000423
611140154402524225
7502163366023031
oct61634354575071
913105325266168
103422614125113
1110aa58249aa77
124733aa666675
131ba99c2c3161
14bb92661c8c1
155e06b628dc8
hex31ce3b2fa39

3422614125113 has 4 divisors (see below), whose sum is σ = 3423415490688. Its totient is φ = 3421812759540.

The previous prime is 3422614125109. The next prime is 3422614125137. The reversal of 3422614125113 is 3115214162243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3422614125113 - 22 = 3422614125109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (3422614125313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 400676381 + ... + 400684922.

It is an arithmetic number, because the mean of its divisors is an integer number (855853872672).

Almost surely, 23422614125113 is an apocalyptic number.

It is an amenable number.

3422614125113 is a deficient number, since it is larger than the sum of its proper divisors (801365575).

3422614125113 is an equidigital number, since it uses as much as digits as its factorization.

3422614125113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 801365574.

The product of its digits is 34560, while the sum is 35.

Adding to 3422614125113 its reverse (3115214162243), we get a palindrome (6537828287356).

The spelling of 3422614125113 in words is "three trillion, four hundred twenty-two billion, six hundred fourteen million, one hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 4271 801361303 3422614125113