Base | Representation |
---|---|
bin | 110001110100000111001… |
… | …101010101101100100011 |
3 | 110010020220101022022111212 |
4 | 301310013031111230203 |
5 | 422041213211402123 |
6 | 11140333443500335 |
7 | 502214221546634 |
oct | 61640715255443 |
9 | 13106811268455 |
10 | 3423209872163 |
11 | 10aa858803604 |
12 | 4735360876ab |
13 | 1baa6585ccc3 |
14 | bb9817b988b |
15 | 5e0a3aa6878 |
hex | 31d07355b23 |
3423209872163 has 2 divisors, whose sum is σ = 3423209872164. Its totient is φ = 3423209872162.
The previous prime is 3423209872099. The next prime is 3423209872171. The reversal of 3423209872163 is 3612789023243.
3423209872163 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3423209872163 - 26 = 3423209872099 is a prime.
It is not a weakly prime, because it can be changed into another prime (3423209872193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1711604936081 + 1711604936082.
It is an arithmetic number, because the mean of its divisors is an integer number (1711604936082).
Almost surely, 23423209872163 is an apocalyptic number.
3423209872163 is a deficient number, since it is larger than the sum of its proper divisors (1).
3423209872163 is an equidigital number, since it uses as much as digits as its factorization.
3423209872163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2612736, while the sum is 50.
The spelling of 3423209872163 in words is "three trillion, four hundred twenty-three billion, two hundred nine million, eight hundred seventy-two thousand, one hundred sixty-three".
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