Base | Representation |
---|---|
bin | 100110111011000000011101… |
… | …1100000101111001110011011 |
3 | 1122220012102200210220212120211 |
4 | 1031312000323200233032123 |
5 | 324333222202433132124 |
6 | 3212050400445431551 |
7 | 132053540300443042 |
oct | 11566007340571633 |
9 | 1586172623825524 |
10 | 342361431536539 |
11 | 9a0a5738838288 |
12 | 32493b3286b5b7 |
13 | 1190571026065c |
14 | 607854b557559 |
15 | 298a916e8de94 |
hex | 137603b82f39b |
342361431536539 has 2 divisors, whose sum is σ = 342361431536540. Its totient is φ = 342361431536538.
The previous prime is 342361431536519. The next prime is 342361431536557. The reversal of 342361431536539 is 935635134163243.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 342361431536539 - 29 = 342361431536027 is a prime.
It is a super-3 number, since 3×3423614315365393 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (342361431536519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 171180715768269 + 171180715768270.
It is an arithmetic number, because the mean of its divisors is an integer number (171180715768270).
Almost surely, 2342361431536539 is an apocalyptic number.
342361431536539 is a deficient number, since it is larger than the sum of its proper divisors (1).
342361431536539 is an equidigital number, since it uses as much as digits as its factorization.
342361431536539 is an evil number, because the sum of its binary digits is even.
The product of its digits is 62985600, while the sum is 58.
The spelling of 342361431536539 in words is "three hundred forty-two trillion, three hundred sixty-one billion, four hundred thirty-one million, five hundred thirty-six thousand, five hundred thirty-nine".
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