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34240013651 = 103332427317
BaseRepresentation
bin11111111000110111…
…010010010101010011
310021101020121220122202
4133320313102111103
51030110420414101
623421334153415
72321333212454
oct377067222523
9107336556582
1034240013651
1113580660048
126776ab286b
1332c894090c
14192b5d912b
15d55eae36b
hex7f8dd2553

34240013651 has 4 divisors (see below), whose sum is σ = 34572441072. Its totient is φ = 33907586232.

The previous prime is 34240013627. The next prime is 34240013669. The reversal of 34240013651 is 15631004243.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15631004243 = 29917522479.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-34240013651 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (34240013611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166213556 + ... + 166213761.

It is an arithmetic number, because the mean of its divisors is an integer number (8643110268).

Almost surely, 234240013651 is an apocalyptic number.

34240013651 is a deficient number, since it is larger than the sum of its proper divisors (332427421).

34240013651 is a wasteful number, since it uses less digits than its factorization.

34240013651 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332427420.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 34240013651 its reverse (15631004243), we get a palindrome (49871017894).

The spelling of 34240013651 in words is "thirty-four billion, two hundred forty million, thirteen thousand, six hundred fifty-one".

Divisors: 1 103 332427317 34240013651