Base | Representation |
---|---|
bin | 110001110100110111000… |
… | …110101011110111101001 |
3 | 110010022222101100111121011 |
4 | 301310313012223313221 |
5 | 422044334414344340 |
6 | 11140545310543521 |
7 | 502243146660550 |
oct | 61646706536751 |
9 | 13108871314534 |
10 | 3424013434345 |
11 | 1100130357789 |
12 | 47371b207ba1 |
13 | 1bab6318c39a |
14 | bba1a3d0d97 |
15 | 5e0ee3d40ea |
hex | 31d371abde9 |
3424013434345 has 16 divisors (see below), whose sum is σ = 4695987484800. Its totient is φ = 2347796110464.
The previous prime is 3424013434343. The next prime is 3424013434357. The reversal of 3424013434345 is 5434343104243.
It is not a de Polignac number, because 3424013434345 - 21 = 3424013434343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3424013434298 and 3424013434307.
It is not an unprimeable number, because it can be changed into a prime (3424013434343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1210252 + ... + 2883181.
It is an arithmetic number, because the mean of its divisors is an integer number (293499217800).
Almost surely, 23424013434345 is an apocalyptic number.
3424013434345 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3424013434345 is a deficient number, since it is larger than the sum of its proper divisors (1271974050455).
3424013434345 is a wasteful number, since it uses less digits than its factorization.
3424013434345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4117344.
The product of its (nonzero) digits is 829440, while the sum is 40.
Adding to 3424013434345 its reverse (5434343104243), we get a palindrome (8858356538588).
The spelling of 3424013434345 in words is "three trillion, four hundred twenty-four billion, thirteen million, four hundred thirty-four thousand, three hundred forty-five".
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