Base | Representation |
---|---|
bin | 110001110101001010000… |
… | …011010101111010111001 |
3 | 110010100210112112000202022 |
4 | 301311022003111322321 |
5 | 422101012304400423 |
6 | 11141041024244225 |
7 | 502254060003026 |
oct | 61651203257271 |
9 | 13110715460668 |
10 | 3424331325113 |
11 | 1100283840826 |
12 | 4737a9770675 |
13 | 1babb3cb252a |
14 | bba4a70054d |
15 | 5e11c278dc8 |
hex | 31d4a0d5eb9 |
3424331325113 has 4 divisors (see below), whose sum is σ = 3424336534500. Its totient is φ = 3424326115728.
The previous prime is 3424331325067. The next prime is 3424331325127. The reversal of 3424331325113 is 3115231334243.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3327366347449 + 96964977664 = 1824107^2 + 311392^2 .
It is a cyclic number.
It is not a de Polignac number, because 3424331325113 - 226 = 3424264216249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3424331325913) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1447238 + ... + 2990511.
It is an arithmetic number, because the mean of its divisors is an integer number (856084133625).
Almost surely, 23424331325113 is an apocalyptic number.
It is an amenable number.
3424331325113 is a deficient number, since it is larger than the sum of its proper divisors (5209387).
3424331325113 is an equidigital number, since it uses as much as digits as its factorization.
3424331325113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5209386.
The product of its digits is 77760, while the sum is 35.
Adding to 3424331325113 its reverse (3115231334243), we get a palindrome (6539562659356).
The spelling of 3424331325113 in words is "three trillion, four hundred twenty-four billion, three hundred thirty-one million, three hundred twenty-five thousand, one hundred thirteen".
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