Base | Representation |
---|---|
bin | 1111100100101010110000… |
… | …00010101001100001110011 |
3 | 11111020210222110001102012011 |
4 | 13302111120002221201303 |
5 | 13442033233320343103 |
6 | 200500015024343351 |
7 | 10133065152401425 |
oct | 762253002514163 |
9 | 144223873042164 |
10 | 34245251340403 |
11 | aa03369678704 |
12 | 3a10b61474b57 |
13 | 161540c5597cc |
14 | 86569c584815 |
15 | 3e5be6c42d6d |
hex | 1f25580a9873 |
34245251340403 has 4 divisors (see below), whose sum is σ = 34245280301328. Its totient is φ = 34245222379480.
The previous prime is 34245251340397. The next prime is 34245251340449. The reversal of 34245251340403 is 30404315254243.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34245251340403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34245251340473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12627751 + ... + 15098032.
It is an arithmetic number, because the mean of its divisors is an integer number (8561320075332).
Almost surely, 234245251340403 is an apocalyptic number.
34245251340403 is a deficient number, since it is larger than the sum of its proper divisors (28960925).
34245251340403 is a wasteful number, since it uses less digits than its factorization.
34245251340403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28960924.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 34245251340403 its reverse (30404315254243), we get a palindrome (64649566594646).
The spelling of 34245251340403 in words is "thirty-four trillion, two hundred forty-five billion, two hundred fifty-one million, three hundred forty thousand, four hundred three".
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