Base | Representation |
---|---|
bin | 11111111001110001… |
… | …010000101110101001 |
3 | 10021102022020001002120 |
4 | 133321301100232221 |
5 | 1030123313231213 |
6 | 23423040021453 |
7 | 2321606331042 |
oct | 377161205651 |
9 | 107368201076 |
10 | 34255211433 |
11 | 135891a03a3 |
12 | 6780001889 |
13 | 32cbb322a1 |
14 | 192d6338c9 |
15 | d574b2423 |
hex | 7f9c50ba9 |
34255211433 has 4 divisors (see below), whose sum is σ = 45673615248. Its totient is φ = 22836807620.
The previous prime is 34255211387. The next prime is 34255211447. The reversal of 34255211433 is 33411255243.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33411255243 = 3 ⋅11137085081.
It is a cyclic number.
It is not a de Polignac number, because 34255211433 - 29 = 34255210921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 34255211394 and 34255211403.
It is not an unprimeable number, because it can be changed into a prime (34255211233) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5709201903 + ... + 5709201908.
It is an arithmetic number, because the mean of its divisors is an integer number (11418403812).
Almost surely, 234255211433 is an apocalyptic number.
It is an amenable number.
34255211433 is a deficient number, since it is larger than the sum of its proper divisors (11418403815).
34255211433 is a wasteful number, since it uses less digits than its factorization.
34255211433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11418403814.
The product of its digits is 43200, while the sum is 33.
Adding to 34255211433 its reverse (33411255243), we get a palindrome (67666466676).
The spelling of 34255211433 in words is "thirty-four billion, two hundred fifty-five million, two hundred eleven thousand, four hundred thirty-three".
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