Base | Representation |
---|---|
bin | 110001111010011000101… |
… | …101101100001010010011 |
3 | 110010220021211112220020120 |
4 | 301322120231230022103 |
5 | 422144012140011103 |
6 | 11143410114441323 |
7 | 502543155045264 |
oct | 61723055541223 |
9 | 13126254486216 |
10 | 3429946016403 |
11 | 11026a5120465 |
12 | 4748b5b93243 |
13 | 1bb59a2b197a |
14 | bc02029096b |
15 | 5e34a151253 |
hex | 31e98b6c293 |
3429946016403 has 4 divisors (see below), whose sum is σ = 4573261355208. Its totient is φ = 2286630677600.
The previous prime is 3429946016401. The next prime is 3429946016503. The reversal of 3429946016403 is 3046106499243.
3429946016403 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3429946016403 - 21 = 3429946016401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3429946016401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 571657669398 + ... + 571657669403.
It is an arithmetic number, because the mean of its divisors is an integer number (1143315338802).
Almost surely, 23429946016403 is an apocalyptic number.
3429946016403 is a deficient number, since it is larger than the sum of its proper divisors (1143315338805).
3429946016403 is a wasteful number, since it uses less digits than its factorization.
3429946016403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1143315338804.
The product of its (nonzero) digits is 3359232, while the sum is 51.
The spelling of 3429946016403 in words is "three trillion, four hundred twenty-nine billion, nine hundred forty-six million, sixteen thousand, four hundred three".
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