Base | Representation |
---|---|
bin | 110001111010011110010… |
… | …101011010000100001011 |
3 | 110010220112101222201101201 |
4 | 301322132111122010023 |
5 | 422144210310022443 |
6 | 11143423323525031 |
7 | 502545411420613 |
oct | 61723625320413 |
9 | 13126471881351 |
10 | 3430040314123 |
11 | 1102743377765 |
12 | 474921689777 |
13 | 1bb5b39a9b37 |
14 | bc02c9d9a43 |
15 | 5e35357b34d |
hex | 31e9e55a10b |
3430040314123 has 2 divisors, whose sum is σ = 3430040314124. Its totient is φ = 3430040314122.
The previous prime is 3430040314109. The next prime is 3430040314193. The reversal of 3430040314123 is 3214130400343.
3430040314123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3430040314123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3430040314091 and 3430040314100.
It is not a weakly prime, because it can be changed into another prime (3430040314193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1715020157061 + 1715020157062.
It is an arithmetic number, because the mean of its divisors is an integer number (1715020157062).
Almost surely, 23430040314123 is an apocalyptic number.
3430040314123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3430040314123 is an equidigital number, since it uses as much as digits as its factorization.
3430040314123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 3430040314123 its reverse (3214130400343), we get a palindrome (6644170714466).
The spelling of 3430040314123 in words is "three trillion, four hundred thirty billion, forty million, three hundred fourteen thousand, one hundred twenty-three".
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