Base | Representation |
---|---|
bin | 110001111010101000101… |
… | …101001111011001100001 |
3 | 110010220222112102211212011 |
4 | 301322220231033121201 |
5 | 422200034332142144 |
6 | 11143452501432521 |
7 | 502552623521416 |
oct | 61725055173141 |
9 | 13126875384764 |
10 | 3430214334049 |
11 | 1102822625488 |
12 | 47496ba0b741 |
13 | 1bb610a68ac9 |
14 | bc047b7810d |
15 | 5e3639a2a34 |
hex | 31ea8b4f661 |
3430214334049 has 2 divisors, whose sum is σ = 3430214334050. Its totient is φ = 3430214334048.
The previous prime is 3430214333993. The next prime is 3430214334101. The reversal of 3430214334049 is 9404334120343.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2705919721024 + 724294613025 = 1644968^2 + 851055^2 .
It is a cyclic number.
It is not a de Polignac number, because 3430214334049 - 237 = 3292775380577 is a prime.
It is not a weakly prime, because it can be changed into another prime (3430214338049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1715107167024 + 1715107167025.
It is an arithmetic number, because the mean of its divisors is an integer number (1715107167025).
Almost surely, 23430214334049 is an apocalyptic number.
It is an amenable number.
3430214334049 is a deficient number, since it is larger than the sum of its proper divisors (1).
3430214334049 is an equidigital number, since it uses as much as digits as its factorization.
3430214334049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 373248, while the sum is 40.
The spelling of 3430214334049 in words is "three trillion, four hundred thirty billion, two hundred fourteen million, three hundred thirty-four thousand, forty-nine".
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