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3430241125657 is a prime number
BaseRepresentation
bin110001111010101010010…
…011011100010100011001
3110010221001101212000000221
4301322222103130110121
5422200113212010112
611143455300000041
7502553400325153
oct61725223342431
913127041760027
103430241125657
111102836764405
12474978990021
131bb616489628
14bc04b54dad3
155e365ee5e07
hex31eaa4dc519

3430241125657 has 2 divisors, whose sum is σ = 3430241125658. Its totient is φ = 3430241125656.

The previous prime is 3430241125627. The next prime is 3430241125679. The reversal of 3430241125657 is 7565211420343.

3430241125657 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3386468535696 + 43772589961 = 1840236^2 + 209219^2 .

It is an emirp because it is prime and its reverse (7565211420343) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3430241125657 is a prime.

It is not a weakly prime, because it can be changed into another prime (3430241125627) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1715120562828 + 1715120562829.

It is an arithmetic number, because the mean of its divisors is an integer number (1715120562829).

Almost surely, 23430241125657 is an apocalyptic number.

It is an amenable number.

3430241125657 is a deficient number, since it is larger than the sum of its proper divisors (1).

3430241125657 is an equidigital number, since it uses as much as digits as its factorization.

3430241125657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 43.

The spelling of 3430241125657 in words is "three trillion, four hundred thirty billion, two hundred forty-one million, one hundred twenty-five thousand, six hundred fifty-seven".