343295040613001 has 4 divisors (see below), whose sum is σ = 343295200960404. Its totient is φ = 343294880265600.

The previous prime is 343295040612943. The next prime is 343295040613039. The reversal of 343295040613001 is 100316040592343.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 297751762585225 + 45543278027776 = 17255485^2 + 6748576^2 .

It is a cyclic number.

It is not a de Polignac number, because 343295040613001 - 2²⁶ = 343294973504137 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 343295040613001.

It is not an unprimeable number, because it can be changed into a prime (343295040613081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76918220 + ... + 81258861.

It is an arithmetic number, because the mean of its divisors is an integer number (85823800240101).

Almost surely, 2^{343295040613001} is an apocalyptic number.

It is an amenable number.

343295040613001 is a deficient number, since it is larger than the sum of its proper divisors (160347403).

343295040613001 is a wasteful number, since it uses less digits than its factorization.

343295040613001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160347402.

The product of its (nonzero) digits is 233280, while the sum is 41.

The spelling of 343295040613001 in words is "three hundred forty-three trillion, two hundred ninety-five billion, forty million, six hundred thirteen thousand, one".