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3434123320000 = 2654593134649
BaseRepresentation
bin110001111110010001101…
…100110101101011000000
3110011022001221212220111121
4301332101230311223000
5422231041032220000
611145340420522024
7503051530410052
oct61762154655300
913138057786447
103434123320000
1111044490a548a
12475680b50314
131bbab4871b49
14bc2d8d998d2
155e4e1c4ab1a
hex31f91b35ac0

3434123320000 has 280 divisors, whose sum is σ = 8689376322000. Its totient is φ = 1345763328000.

The previous prime is 3434123319973. The next prime is 3434123320073. The reversal of 3434123320000 is 233214343.

3434123320000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 738677676 + ... + 738682324.

Almost surely, 23434123320000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3434123320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4344688161000).

3434123320000 is an abundant number, since it is smaller than the sum of its proper divisors (5255253002000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3434123320000 is an equidigital number, since it uses as much as digits as its factorization.

3434123320000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5053 (or 5028 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 3434123320000 its reverse (233214343), we get a palindrome (3434356534343).

The spelling of 3434123320000 in words is "three trillion, four hundred thirty-four billion, one hundred twenty-three million, three hundred twenty thousand".