Base | Representation |
---|---|
bin | 110001111111011110001… |
… | …000000100000110011001 |
3 | 110011102101022120200122112 |
4 | 301333132020010012121 |
5 | 422241202303303101 |
6 | 11150111543002105 |
7 | 503125360105163 |
oct | 61773610040631 |
9 | 13142338520575 |
10 | 3435405525401 |
11 | 1104a46949373 |
12 | 47597a439335 |
13 | 1bbc5a3b9475 |
14 | bc3bb3a7933 |
15 | 5e5695c36bb |
hex | 31fde204199 |
3435405525401 has 4 divisors (see below), whose sum is σ = 3508499260032. Its totient is φ = 3362311790772.
The previous prime is 3435405525373. The next prime is 3435405525403. The reversal of 3435405525401 is 1045255045343.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3435405525401 is a prime.
It is a super-2 number, since 2×34354055254012 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3435405525403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36546867245 + ... + 36546867338.
It is an arithmetic number, because the mean of its divisors is an integer number (877124815008).
Almost surely, 23435405525401 is an apocalyptic number.
It is an amenable number.
3435405525401 is a deficient number, since it is larger than the sum of its proper divisors (73093734631).
3435405525401 is an equidigital number, since it uses as much as digits as its factorization.
3435405525401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73093734630.
The product of its (nonzero) digits is 720000, while the sum is 41.
The spelling of 3435405525401 in words is "three trillion, four hundred thirty-five billion, four hundred five million, five hundred twenty-five thousand, four hundred one".
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