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343717131217393 = 1339792565455267
BaseRepresentation
bin100111000100110111110000…
…1100000100110100111110001
31200002000000222212001021200201
41032021233201200212213301
5330022430141042424033
63215005245322515201
7132253512634546513
oct11611574140464761
91602000885037621
10343717131217393
119a57868698106a
1232672823965b01
13119a3503bb341b
1460c3dd83c7bb3
1529b0d10d1d47d
hex1389be18269f1

343717131217393 has 4 divisors (see below), whose sum is σ = 343719696806640. Its totient is φ = 343714565628148.

The previous prime is 343717131217337. The next prime is 343717131217403. The reversal of 343717131217393 is 393712131717343.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 343717131217393 - 213 = 343717131209201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (343717131287393) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1282593655 + ... + 1282861612.

It is an arithmetic number, because the mean of its divisors is an integer number (85929924201660).

Almost surely, 2343717131217393 is an apocalyptic number.

It is an amenable number.

343717131217393 is a deficient number, since it is larger than the sum of its proper divisors (2565589247).

343717131217393 is a wasteful number, since it uses less digits than its factorization.

343717131217393 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2565589246.

The product of its digits is 6001128, while the sum is 55.

The spelling of 343717131217393 in words is "three hundred forty-three trillion, seven hundred seventeen billion, one hundred thirty-one million, two hundred seventeen thousand, three hundred ninety-three".

Divisors: 1 133979 2565455267 343717131217393