Base | Representation |
---|---|
bin | 100111000100110111110000… |
… | …1100000100110100111110001 |
3 | 1200002000000222212001021200201 |
4 | 1032021233201200212213301 |
5 | 330022430141042424033 |
6 | 3215005245322515201 |
7 | 132253512634546513 |
oct | 11611574140464761 |
9 | 1602000885037621 |
10 | 343717131217393 |
11 | 9a57868698106a |
12 | 32672823965b01 |
13 | 119a3503bb341b |
14 | 60c3dd83c7bb3 |
15 | 29b0d10d1d47d |
hex | 1389be18269f1 |
343717131217393 has 4 divisors (see below), whose sum is σ = 343719696806640. Its totient is φ = 343714565628148.
The previous prime is 343717131217337. The next prime is 343717131217403. The reversal of 343717131217393 is 393712131717343.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 343717131217393 - 213 = 343717131209201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (343717131287393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1282593655 + ... + 1282861612.
It is an arithmetic number, because the mean of its divisors is an integer number (85929924201660).
Almost surely, 2343717131217393 is an apocalyptic number.
It is an amenable number.
343717131217393 is a deficient number, since it is larger than the sum of its proper divisors (2565589247).
343717131217393 is a wasteful number, since it uses less digits than its factorization.
343717131217393 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2565589246.
The product of its digits is 6001128, while the sum is 55.
The spelling of 343717131217393 in words is "three hundred forty-three trillion, seven hundred seventeen billion, one hundred thirty-one million, two hundred seventeen thousand, three hundred ninety-three".
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