Base | Representation |
---|---|
bin | 110010000011111001110… |
… | …011101010101101100001 |
3 | 110011212200000012101000102 |
4 | 302003321303222231201 |
5 | 422330424204022443 |
6 | 11152220121032145 |
7 | 503354331145631 |
oct | 62037163525541 |
9 | 13155600171012 |
10 | 3440164907873 |
11 | 1106a69450911 |
12 | 476888325655 |
13 | 1bc53843c105 |
14 | bc70d5126c1 |
15 | 5e74734acb8 |
hex | 320f9ceab61 |
3440164907873 has 2 divisors, whose sum is σ = 3440164907874. Its totient is φ = 3440164907872.
The previous prime is 3440164907867. The next prime is 3440164907903. The reversal of 3440164907873 is 3787094610443.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2841844093729 + 598320814144 = 1685777^2 + 773512^2 .
It is an emirp because it is prime and its reverse (3787094610443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3440164907873 - 222 = 3440160713569 is a prime.
It is not a weakly prime, because it can be changed into another prime (3440164909873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1720082453936 + 1720082453937.
It is an arithmetic number, because the mean of its divisors is an integer number (1720082453937).
Almost surely, 23440164907873 is an apocalyptic number.
It is an amenable number.
3440164907873 is a deficient number, since it is larger than the sum of its proper divisors (1).
3440164907873 is an equidigital number, since it uses as much as digits as its factorization.
3440164907873 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12192768, while the sum is 56.
The spelling of 3440164907873 in words is "three trillion, four hundred forty billion, one hundred sixty-four million, nine hundred seven thousand, eight hundred seventy-three".
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