Search a number
-
+
34412332441441 is a prime number
BaseRepresentation
bin1111101001100001111101…
…10110011101111101100001
311111211210020121121202200111
413310300332312131331201
514002302424101111231
6201104450212251321
710151131451334163
oct764607666357541
9144753217552614
1034412332441441
11aa68208598889
123a39410610b41
1316280b8856936
1486d7cc6c6933
153ea2251b94b1
hex1f4c3ed9df61

34412332441441 has 2 divisors, whose sum is σ = 34412332441442. Its totient is φ = 34412332441440.

The previous prime is 34412332441433. The next prime is 34412332441453. The reversal of 34412332441441 is 14414423321443.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28316020838400 + 6096311603041 = 5321280^2 + 2469071^2 .

It is a cyclic number.

It is not a de Polignac number, because 34412332441441 - 23 = 34412332441433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34412332441394 and 34412332441403.

It is not a weakly prime, because it can be changed into another prime (34412332481441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17206166220720 + 17206166220721.

It is an arithmetic number, because the mean of its divisors is an integer number (17206166220721).

Almost surely, 234412332441441 is an apocalyptic number.

It is an amenable number.

34412332441441 is a deficient number, since it is larger than the sum of its proper divisors (1).

34412332441441 is an equidigital number, since it uses as much as digits as its factorization.

34412332441441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 442368, while the sum is 40.

Adding to 34412332441441 its reverse (14414423321443), we get a palindrome (48826755762884).

The spelling of 34412332441441 in words is "thirty-four trillion, four hundred twelve billion, three hundred thirty-two million, four hundred forty-one thousand, four hundred forty-one".