Base | Representation |
---|---|
bin | 110010000101000110011… |
… | …010110111110001111001 |
3 | 110011222222120210200122112 |
4 | 302011012122313301321 |
5 | 422341042231102213 |
6 | 11152551434302105 |
7 | 503431226333033 |
oct | 62050632676171 |
9 | 13158876720575 |
10 | 3441450253433 |
11 | 1107568a49a75 |
12 | 476b86887935 |
13 | 1bc6b1815b0a |
14 | bc7d20dac53 |
15 | 5e7c00e3ea8 |
hex | 321466b7c79 |
3441450253433 has 8 divisors (see below), whose sum is σ = 3623154444000. Its totient is φ = 3259803585888.
The previous prime is 3441450253421. The next prime is 3441450253511. The reversal of 3441450253433 is 3343520541443.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3441450253433 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3441450283433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14257916 + ... + 14497277.
It is an arithmetic number, because the mean of its divisors is an integer number (452894305500).
Almost surely, 23441450253433 is an apocalyptic number.
It is an amenable number.
3441450253433 is a deficient number, since it is larger than the sum of its proper divisors (181704190567).
3441450253433 is a wasteful number, since it uses less digits than its factorization.
3441450253433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28761511.
The product of its (nonzero) digits is 1036800, while the sum is 41.
Adding to 3441450253433 its reverse (3343520541443), we get a palindrome (6784970794876).
The spelling of 3441450253433 in words is "three trillion, four hundred forty-one billion, four hundred fifty million, two hundred fifty-three thousand, four hundred thirty-three".
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