Base | Representation |
---|---|
bin | 100111001001010010110101… |
… | …1001100001001100101010001 |
3 | 1200011011011002110200021200122 |
4 | 1032102211223030021211101 |
5 | 330112410131031000423 |
6 | 3220152422531400025 |
7 | 132345443160650666 |
oct | 11622455314114521 |
9 | 1604134073607618 |
10 | 344325031500113 |
11 | 9a792475823a34 |
12 | 327505b8453015 |
13 | 11a1893250bb21 |
14 | 61055c59b9a6d |
15 | 29c1a3e53a8c8 |
hex | 139296b309951 |
344325031500113 has 2 divisors, whose sum is σ = 344325031500114. Its totient is φ = 344325031500112.
The previous prime is 344325031500083. The next prime is 344325031500179. The reversal of 344325031500113 is 311005130523443.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 193182423384064 + 151142608116049 = 13899008^2 + 12294007^2 .
It is a cyclic number.
It is not a de Polignac number, because 344325031500113 - 228 = 344324763064657 is a prime.
It is not a weakly prime, because it can be changed into another prime (344325031500193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172162515750056 + 172162515750057.
It is an arithmetic number, because the mean of its divisors is an integer number (172162515750057).
Almost surely, 2344325031500113 is an apocalyptic number.
It is an amenable number.
344325031500113 is a deficient number, since it is larger than the sum of its proper divisors (1).
344325031500113 is an equidigital number, since it uses as much as digits as its factorization.
344325031500113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
The spelling of 344325031500113 in words is "three hundred forty-four trillion, three hundred twenty-five billion, thirty-one million, five hundred thousand, one hundred thirteen".
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