Base | Representation |
---|---|
bin | 110010000111100100100… |
… | …010101100001011000011 |
3 | 110012020211110121102100112 |
4 | 302013210202230023003 |
5 | 422412010343300141 |
6 | 11154111002141535 |
7 | 503554041230603 |
oct | 62074442541303 |
9 | 13166743542315 |
10 | 3444103103171 |
11 | 11086aa461275 |
12 | 4775a71b18ab |
13 | 1bca153012a3 |
14 | bc9a4578c03 |
15 | 5e8c7e637eb |
hex | 321e48ac2c3 |
3444103103171 has 2 divisors, whose sum is σ = 3444103103172. Its totient is φ = 3444103103170.
The previous prime is 3444103103041. The next prime is 3444103103197. The reversal of 3444103103171 is 1713013014443.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3444103103171 is a prime.
It is a super-2 number, since 2×34441031031712 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3444103105171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1722051551585 + 1722051551586.
It is an arithmetic number, because the mean of its divisors is an integer number (1722051551586).
Almost surely, 23444103103171 is an apocalyptic number.
3444103103171 is a deficient number, since it is larger than the sum of its proper divisors (1).
3444103103171 is an equidigital number, since it uses as much as digits as its factorization.
3444103103171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 3444103103171 in words is "three trillion, four hundred forty-four billion, one hundred three million, one hundred three thousand, one hundred seventy-one".
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