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344413433 = 7136756489
BaseRepresentation
bin10100100001110…
…101010011111001
3220000002000102002
4110201311103321
51201132212213
654101550345
711351315540
oct2441652371
9800060362
10344413433
11167459a01
12974153b5
135647b440
1433a55157
1520383658
hex148754f9

344413433 has 16 divisors (see below), whose sum is σ = 430227840. Its totient is φ = 268430976.

The previous prime is 344413373. The next prime is 344413439. The reversal of 344413433 is 334314443.

It is a cyclic number.

It is not a de Polignac number, because 344413433 - 26 = 344413369 is a prime.

It is a super-2 number, since 2×3444134332 = 237241225661690978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 344413396 and 344413405.

It is not an unprimeable number, because it can be changed into a prime (344413439) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22148 + ... + 34341.

It is an arithmetic number, because the mean of its divisors is an integer number (26889240).

Almost surely, 2344413433 is an apocalyptic number.

It is an amenable number.

344413433 is a deficient number, since it is larger than the sum of its proper divisors (85814407).

344413433 is a wasteful number, since it uses less digits than its factorization.

344413433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56576.

The product of its digits is 20736, while the sum is 29.

The square root of 344413433 is about 18558.3790509840. The cubic root of 344413433 is about 700.9602013217.

Adding to 344413433 its reverse (334314443), we get a palindrome (678727876).

The spelling of 344413433 in words is "three hundred forty-four million, four hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 7 13 67 91 469 871 6097 56489 395423 734357 3784763 5140499 26493341 49201919 344413433