Base | Representation |
---|---|
bin | 100000000111000110… |
… | …000000101010000001 |
3 | 10021222212212012102221 |
4 | 200013012000222001 |
5 | 1031103030120213 |
6 | 23501143211041 |
7 | 2330262401644 |
oct | 400706005201 |
9 | 107885765387 |
10 | 34478754433 |
11 | 136933a3582 |
12 | 6822a46a81 |
13 | 3336240556 |
14 | 19511c3a5b |
15 | d6be1c38d |
hex | 807180a81 |
34478754433 has 2 divisors, whose sum is σ = 34478754434. Its totient is φ = 34478754432.
The previous prime is 34478754419. The next prime is 34478754437. The reversal of 34478754433 is 33445787443.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33801557904 + 677196529 = 183852^2 + 26023^2 .
It is a cyclic number.
It is not a de Polignac number, because 34478754433 - 225 = 34445200001 is a prime.
It is a super-2 number, since 2×344787544332 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (34478754437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17239377216 + 17239377217.
It is an arithmetic number, because the mean of its divisors is an integer number (17239377217).
Almost surely, 234478754433 is an apocalyptic number.
It is an amenable number.
34478754433 is a deficient number, since it is larger than the sum of its proper divisors (1).
34478754433 is an equidigital number, since it uses as much as digits as its factorization.
34478754433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 13547520, while the sum is 52.
The spelling of 34478754433 in words is "thirty-four billion, four hundred seventy-eight million, seven hundred fifty-four thousand, four hundred thirty-three".
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