Base | Representation |
---|---|
bin | 1010000010010011011… |
… | …11101001111110010011 |
3 | 1012222002010011100200111 |
4 | 11001021233221332103 |
5 | 21122210130110024 |
6 | 422225334302151 |
7 | 33625215564232 |
oct | 5011157517623 |
9 | 1188063140614 |
10 | 344834613139 |
11 | 123275170795 |
12 | 569b84b7957 |
13 | 266966b43b3 |
14 | 1299383cb19 |
15 | 8e8382da94 |
hex | 5049be9f93 |
344834613139 has 2 divisors, whose sum is σ = 344834613140. Its totient is φ = 344834613138.
The previous prime is 344834613103. The next prime is 344834613181. The reversal of 344834613139 is 931316438443.
It is a weak prime.
It is an emirp because it is prime and its reverse (931316438443) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 344834613139 - 211 = 344834611091 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 344834613092 and 344834613101.
It is not a weakly prime, because it can be changed into another prime (344834613239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172417306569 + 172417306570.
It is an arithmetic number, because the mean of its divisors is an integer number (172417306570).
Almost surely, 2344834613139 is an apocalyptic number.
344834613139 is a deficient number, since it is larger than the sum of its proper divisors (1).
344834613139 is an equidigital number, since it uses as much as digits as its factorization.
344834613139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2239488, while the sum is 49.
The spelling of 344834613139 in words is "three hundred forty-four billion, eight hundred thirty-four million, six hundred thirteen thousand, one hundred thirty-nine".
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