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34503346031953 is a prime number
BaseRepresentation
bin1111101100001011011111…
…01011110000110101010001
311112011111011111202012121011
413312011233223300311101
514010300323041010303
6201214341321330521
710160533036154131
oct766055753606521
9145144144665534
1034503346031953
11aaa2872375487
123a52b90936a41
131633861663cc6
14873d8406cac1
153ec7a050e16d
hex1f616faf0d51

34503346031953 has 2 divisors, whose sum is σ = 34503346031954. Its totient is φ = 34503346031952.

The previous prime is 34503346031851. The next prime is 34503346031963. The reversal of 34503346031953 is 35913064330543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19345148449344 + 15158197582609 = 4398312^2 + 3893353^2 .

It is a cyclic number.

It is not a de Polignac number, because 34503346031953 - 225 = 34503312477521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 34503346031897 and 34503346031906.

It is not a weakly prime, because it can be changed into another prime (34503346031963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17251673015976 + 17251673015977.

It is an arithmetic number, because the mean of its divisors is an integer number (17251673015977).

Almost surely, 234503346031953 is an apocalyptic number.

It is an amenable number.

34503346031953 is a deficient number, since it is larger than the sum of its proper divisors (1).

34503346031953 is an equidigital number, since it uses as much as digits as its factorization.

34503346031953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5248800, while the sum is 49.

The spelling of 34503346031953 in words is "thirty-four trillion, five hundred three billion, three hundred forty-six million, thirty-one thousand, nine hundred fifty-three".