Base | Representation |
---|---|
bin | 110010001101100010011… |
… | …001101100100011100010 |
3 | 110012212100221122022101201 |
4 | 302031202121230203202 |
5 | 423013120432020304 |
6 | 11201050420351414 |
7 | 504201563013334 |
oct | 62154231544342 |
9 | 13185327568351 |
10 | 3450509641954 |
11 | 1110397813721 |
12 | 47889484556a |
13 | 1c04c668a93b |
14 | bd011371454 |
15 | 5eb506023a4 |
hex | 3236266c8e2 |
3450509641954 has 16 divisors (see below), whose sum is σ = 5318106757920. Its totient is φ = 1678140354240.
The previous prime is 3450509641939. The next prime is 3450509641979. The reversal of 3450509641954 is 4591469050543.
It is a happy number.
It is a super-3 number, since 3×34505096419543 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3450509641895 and 3450509641904.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 83220364 + ... + 83261815.
It is an arithmetic number, because the mean of its divisors is an integer number (332381672370).
Almost surely, 23450509641954 is an apocalyptic number.
3450509641954 is a deficient number, since it is larger than the sum of its proper divisors (1867597115966).
3450509641954 is a wasteful number, since it uses less digits than its factorization.
3450509641954 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 166482465.
The product of its (nonzero) digits is 11664000, while the sum is 55.
The spelling of 3450509641954 in words is "three trillion, four hundred fifty billion, five hundred nine million, six hundred forty-one thousand, nine hundred fifty-four".
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