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345054401772099 = 3115018133924033
BaseRepresentation
bin100111001110100110011110…
…1000010111011101001000011
31200020201212201112112002100220
41032131030331002323221003
5330211332403323201344
63221511445343514123
7132452233512660435
oct11635147502735103
91606655645462326
10345054401772099
119aa43828283688
1232849a30bb8943
1311a6c64b737016
14612ca17844655
1529d59cbccac19
hex139d33d0bba43

345054401772099 has 4 divisors (see below), whose sum is σ = 460072535696136. Its totient is φ = 230036267848064.

The previous prime is 345054401772089. The next prime is 345054401772121. The reversal of 345054401772099 is 990277104450543.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 345054401772099 - 215 = 345054401739331 is a prime.

It is a super-3 number, since 3×3450544017720993 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (345054401772089) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57509066962014 + ... + 57509066962019.

It is an arithmetic number, because the mean of its divisors is an integer number (115018133924034).

Almost surely, 2345054401772099 is an apocalyptic number.

345054401772099 is a deficient number, since it is larger than the sum of its proper divisors (115018133924037).

345054401772099 is a wasteful number, since it uses less digits than its factorization.

345054401772099 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115018133924036.

The product of its (nonzero) digits is 38102400, while the sum is 60.

The spelling of 345054401772099 in words is "three hundred forty-five trillion, fifty-four billion, four hundred one million, seven hundred seventy-two thousand, ninety-nine".

Divisors: 1 3 115018133924033 345054401772099