Base | Representation |
---|---|
bin | 110010001110000010110… |
… | …111011010101101100011 |
3 | 110012220202220112000101202 |
4 | 302032002313122231203 |
5 | 423020224400212344 |
6 | 11201220434351415 |
7 | 504221225403533 |
oct | 62160267325543 |
9 | 13186686460352 |
10 | 3451054304099 |
11 | 1110647205426 |
12 | 478a0712b56b |
13 | 1c058247c62c |
14 | bd0638314c3 |
15 | 5eb8333d94e |
hex | 32382ddab63 |
3451054304099 has 2 divisors, whose sum is σ = 3451054304100. Its totient is φ = 3451054304098.
The previous prime is 3451054304057. The next prime is 3451054304129. The reversal of 3451054304099 is 9904034501543.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3451054304099 - 236 = 3382334827363 is a prime.
It is a super-4 number, since 4×34510543040994 (a number of 51 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (3451054304899) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1725527152049 + 1725527152050.
It is an arithmetic number, because the mean of its divisors is an integer number (1725527152050).
Almost surely, 23451054304099 is an apocalyptic number.
3451054304099 is a deficient number, since it is larger than the sum of its proper divisors (1).
3451054304099 is an equidigital number, since it uses as much as digits as its factorization.
3451054304099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1166400, while the sum is 47.
The spelling of 3451054304099 in words is "three trillion, four hundred fifty-one billion, fifty-four million, three hundred four thousand, ninety-nine".
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