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345125503993 is a prime number
BaseRepresentation
bin1010000010110110001…
…01010100001111111001
31012222211101112010220211
411001123011110033321
521123304112111433
6422314245151121
733635350244434
oct5013305241771
91188741463824
10345125503993
11123404393356
1256a799bb4a1
1326711a42c6a
14129c032081b
158e9e13d8cd
hex505b1543f9

345125503993 has 2 divisors, whose sum is σ = 345125503994. Its totient is φ = 345125503992.

The previous prime is 345125503937. The next prime is 345125504041. The reversal of 345125503993 is 399305521543.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 252659033104 + 92466470889 = 502652^2 + 304083^2 .

It is an emirp because it is prime and its reverse (399305521543) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 345125503993 - 233 = 336535569401 is a prime.

It is a super-2 number, since 2×3451255039932 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (345125503693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172562751996 + 172562751997.

It is an arithmetic number, because the mean of its divisors is an integer number (172562751997).

Almost surely, 2345125503993 is an apocalyptic number.

It is an amenable number.

345125503993 is a deficient number, since it is larger than the sum of its proper divisors (1).

345125503993 is an equidigital number, since it uses as much as digits as its factorization.

345125503993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187000, while the sum is 49.

The spelling of 345125503993 in words is "three hundred forty-five billion, one hundred twenty-five million, five hundred three thousand, nine hundred ninety-three".