Base | Representation |
---|---|
bin | 100000001011000000… |
… | …100110000100000011 |
3 | 10022011110110120002221 |
4 | 200023000212010003 |
5 | 1031221334144101 |
6 | 23511451151511 |
7 | 2332020632464 |
oct | 401300460403 |
9 | 108143416087 |
10 | 34544443651 |
11 | 1371748a893 |
12 | 6840a45597 |
13 | 3346a2cc03 |
14 | 1959c02d6b |
15 | d72a95aa1 |
hex | 80b026103 |
34544443651 has 2 divisors, whose sum is σ = 34544443652. Its totient is φ = 34544443650.
The previous prime is 34544443597. The next prime is 34544443667. The reversal of 34544443651 is 15634444543.
It is a strong prime.
It is an emirp because it is prime and its reverse (15634444543) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34544443651 is a prime.
It is a super-2 number, since 2×345444436512 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34544443598 and 34544443607.
It is not a weakly prime, because it can be changed into another prime (34544443051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17272221825 + 17272221826.
It is an arithmetic number, because the mean of its divisors is an integer number (17272221826).
Almost surely, 234544443651 is an apocalyptic number.
34544443651 is a deficient number, since it is larger than the sum of its proper divisors (1).
34544443651 is an equidigital number, since it uses as much as digits as its factorization.
34544443651 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1382400, while the sum is 43.
The spelling of 34544443651 in words is "thirty-four billion, five hundred forty-four million, four hundred forty-three thousand, six hundred fifty-one".
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