34550425130051 has 4 divisors (see below), whose sum is σ = 34550479191312. Its totient is φ = 34550371068792.

The previous prime is 34550425130041. The next prime is 34550425130069. The reversal of 34550425130051 is 15003152405543.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 34550425130051 - 2¹⁰ = 34550425129027 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 34550425129987 and 34550425130014.

It is not an unprimeable number, because it can be changed into a prime (34550425130021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26060375 + ... + 27354048.

It is an arithmetic number, because the mean of its divisors is an integer number (8637619797828).

Almost surely, 2^{34550425130051} is an apocalyptic number.

34550425130051 is a deficient number, since it is larger than the sum of its proper divisors (54061261).

34550425130051 is an equidigital number, since it uses as much as digits as its factorization.

34550425130051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54061260.

The product of its (nonzero) digits is 180000, while the sum is 38.

Adding to 34550425130051 its reverse (15003152405543), we get a palindrome (49553577535594).

The spelling of 34550425130051 in words is "thirty-four trillion, five hundred fifty billion, four hundred twenty-five million, one hundred thirty thousand, fifty-one".