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347042323240747 is a prime number
BaseRepresentation
bin100111011101000100001011…
…0011001100001011100101011
31200111202220220012110222012221
41032322020112121201130223
5330441420134222200442
63230033013052014511
7133045660201443421
oct11672102631413453
91614686805428187
10347042323240747
11a063a906105052
1232b0b163a61437
1311b84c4879bb04
14619ad1c0b3111
152a1c5796c4467
hex13ba21666172b

347042323240747 has 2 divisors, whose sum is σ = 347042323240748. Its totient is φ = 347042323240746.

The previous prime is 347042323240727. The next prime is 347042323240759. The reversal of 347042323240747 is 747042323240743.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-347042323240747 is a prime.

It is a super-2 number, since 2×3470423232407472 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 347042323240694 and 347042323240703.

It is not a weakly prime, because it can be changed into another prime (347042323240727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 173521161620373 + 173521161620374.

It is an arithmetic number, because the mean of its divisors is an integer number (173521161620374).

Almost surely, 2347042323240747 is an apocalyptic number.

347042323240747 is a deficient number, since it is larger than the sum of its proper divisors (1).

347042323240747 is an equidigital number, since it uses as much as digits as its factorization.

347042323240747 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18966528, while the sum is 52.

The spelling of 347042323240747 in words is "three hundred forty-seven trillion, forty-two billion, three hundred twenty-three million, two hundred forty thousand, seven hundred forty-seven".