Base | Representation |
---|---|
bin | 1010001000110001010… |
… | …10011101010101001011 |
3 | 1020022001001102220112001 |
4 | 11010120222131111023 |
5 | 21201312332244342 |
6 | 424002025131431 |
7 | 34110231202303 |
oct | 5043052352513 |
9 | 1208031386461 |
10 | 348306134347 |
11 | 124796806a86 |
12 | 57607029b77 |
13 | 26aca98c262 |
14 | 12c02906603 |
15 | 90d84b28b7 |
hex | 5118a9d54b |
348306134347 has 2 divisors, whose sum is σ = 348306134348. Its totient is φ = 348306134346.
The previous prime is 348306134321. The next prime is 348306134401. The reversal of 348306134347 is 743431603843.
It is a weak prime.
It is an emirp because it is prime and its reverse (743431603843) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 348306134347 - 215 = 348306101579 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 348306134297 and 348306134306.
It is not a weakly prime, because it can be changed into another prime (348306134317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174153067173 + 174153067174.
It is an arithmetic number, because the mean of its divisors is an integer number (174153067174).
Almost surely, 2348306134347 is an apocalyptic number.
348306134347 is a deficient number, since it is larger than the sum of its proper divisors (1).
348306134347 is an equidigital number, since it uses as much as digits as its factorization.
348306134347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 46.
It can be divided in two parts, 348306 and 134347, that added together give a triangular number (482653 = T982).
The spelling of 348306134347 in words is "three hundred forty-eight billion, three hundred six million, one hundred thirty-four thousand, three hundred forty-seven".
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