3485064365113 has 4 divisors (see below), whose sum is σ = 3566112373648. Its totient is φ = 3404016356580.

The previous prime is 3485064365063. The next prime is 3485064365129. The reversal of 3485064365113 is 3115634605843.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3485064365113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3485064365413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40524004203 + ... + 40524004288.

It is an arithmetic number, because the mean of its divisors is an integer number (891528093412).

Almost surely, 2^{3485064365113} is an apocalyptic number.

It is an amenable number.

3485064365113 is a deficient number, since it is larger than the sum of its proper divisors (81048008535).

3485064365113 is an equidigital number, since it uses as much as digits as its factorization.

3485064365113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81048008534.

The product of its (nonzero) digits is 3110400, while the sum is 49.

The spelling of 3485064365113 in words is "three trillion, four hundred eighty-five billion, sixty-four million, three hundred sixty-five thousand, one hundred thirteen".