3499040506147 has 2 divisors, whose sum is σ = 3499040506148. Its totient is φ = 3499040506146.

The previous prime is 3499040506139. The next prime is 3499040506201. The reversal of 3499040506147 is 7416050409943.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3499040506147 - 2³ = 3499040506139 is a prime.

It is a super-3 number, since 3×3499040506147³ (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3499040506094 and 3499040506103.

It is not a weakly prime, because it can be changed into another prime (3499040506127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1749520253073 + 1749520253074.

It is an arithmetic number, because the mean of its divisors is an integer number (1749520253074).

Almost surely, 2^{3499040506147} is an apocalyptic number.

3499040506147 is a deficient number, since it is larger than the sum of its proper divisors (1).

3499040506147 is an equidigital number, since it uses as much as digits as its factorization.

3499040506147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 52.

The spelling of 3499040506147 in words is "three trillion, four hundred ninety-nine billion, forty million, five hundred six thousand, one hundred forty-seven".