Base | Representation |
---|---|
bin | 1010001011111100100… |
… | …10110111110001100001 |
3 | 1020110102212212121020102 |
4 | 11011332102313301201 |
5 | 21213310333232413 |
6 | 424443135152145 |
7 | 34200414225503 |
oct | 5057622676141 |
9 | 1213385777212 |
10 | 350011227233 |
11 | 125491238558 |
12 | 57a02075655 |
13 | 2700cccc965 |
14 | 12d25155d73 |
15 | 9188020458 |
hex | 517e4b7c61 |
350011227233 has 2 divisors, whose sum is σ = 350011227234. Its totient is φ = 350011227232.
The previous prime is 350011227221. The next prime is 350011227253. The reversal of 350011227233 is 332722110053.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 206163218704 + 143848008529 = 454052^2 + 379273^2 .
It is a cyclic number.
It is not a de Polignac number, because 350011227233 - 24 = 350011227217 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 350011227196 and 350011227205.
It is not a weakly prime, because it can be changed into another prime (350011227253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175005613616 + 175005613617.
It is an arithmetic number, because the mean of its divisors is an integer number (175005613617).
Almost surely, 2350011227233 is an apocalyptic number.
It is an amenable number.
350011227233 is a deficient number, since it is larger than the sum of its proper divisors (1).
350011227233 is an equidigital number, since it uses as much as digits as its factorization.
350011227233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 29.
Adding to 350011227233 its reverse (332722110053), we get a palindrome (682733337286).
The spelling of 350011227233 in words is "three hundred fifty billion, eleven million, two hundred twenty-seven thousand, two hundred thirty-three".
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