Base | Representation |
---|---|
bin | 1111111011000001100111… |
… | …01101110101101001101010 |
3 | 11120222020210220112000220222 |
4 | 13331200303231311221222 |
5 | 14042130011402114432 |
6 | 202244541444050042 |
7 | 10242431465244563 |
oct | 775406355655152 |
9 | 146866726460828 |
10 | 35013441051242 |
11 | 1017a131747325 |
12 | 3b15a0a693922 |
13 | 166c9a408a974 |
14 | 890933cab16a |
15 | 40aba751e112 |
hex | 1fd833b75a6a |
35013441051242 has 4 divisors (see below), whose sum is σ = 52520161576866. Its totient is φ = 17506720525620.
The previous prime is 35013441051187. The next prime is 35013441051247. The reversal of 35013441051242 is 24215014431053.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 34995021404281 + 18419646961 = 5915659^2 + 135719^2 .
It is a super-3 number, since 3×350134410512423 (a number of 42 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (35013441051247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8753360262809 + ... + 8753360262812.
Almost surely, 235013441051242 is an apocalyptic number.
35013441051242 is a deficient number, since it is larger than the sum of its proper divisors (17506720525624).
35013441051242 is a wasteful number, since it uses less digits than its factorization.
35013441051242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17506720525623.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 35013441051242 its reverse (24215014431053), we get a palindrome (59228455482295).
The spelling of 35013441051242 in words is "thirty-five trillion, thirteen billion, four hundred forty-one million, fifty-one thousand, two hundred forty-two".
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