Base | Representation |
---|---|
bin | 100111110101000110001010… |
… | …1110000001000011110000001 |
3 | 1200221110200001100010022222121 |
4 | 1033222030111300020132001 |
5 | 331410023322403204103 |
6 | 3241042200401404241 |
7 | 133536413136645223 |
oct | 11752142560103601 |
9 | 1627420040108877 |
10 | 350345142241153 |
11 | a16a35a4352824 |
12 | 3336329b339681 |
13 | 1206453617ac97 |
14 | 6272b1c67a413 |
15 | 2a78433d166bd |
hex | 13ea315c08781 |
350345142241153 has 2 divisors, whose sum is σ = 350345142241154. Its totient is φ = 350345142241152.
The previous prime is 350345142241021. The next prime is 350345142241169. The reversal of 350345142241153 is 351142241543053.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 177511735162609 + 172833407078544 = 13323353^2 + 13146612^2 .
It is a cyclic number.
It is not a de Polignac number, because 350345142241153 - 213 = 350345142232961 is a prime.
It is not a weakly prime, because it can be changed into another prime (350345142271153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175172571120576 + 175172571120577.
It is an arithmetic number, because the mean of its divisors is an integer number (175172571120577).
Almost surely, 2350345142241153 is an apocalyptic number.
It is an amenable number.
350345142241153 is a deficient number, since it is larger than the sum of its proper divisors (1).
350345142241153 is an equidigital number, since it uses as much as digits as its factorization.
350345142241153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864000, while the sum is 43.
The spelling of 350345142241153 in words is "three hundred fifty trillion, three hundred forty-five billion, one hundred forty-two million, two hundred forty-one thousand, one hundred fifty-three".
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