351013540433 has 4 divisors (see below), whose sum is σ = 353338133568. Its totient is φ = 348688947300.

The previous prime is 351013540429. The next prime is 351013540439. The reversal of 351013540433 is 334045310153.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 351013540433 - 2² = 351013540429 is a prime.

It is a super-3 number, since 3×351013540433³ (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 351013540433.

It is not an unprimeable number, because it can be changed into a prime (351013540439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1162296341 + ... + 1162296642.

It is an arithmetic number, because the mean of its divisors is an integer number (88334533392).

Almost surely, 2^351013540433 is an apocalyptic number.

It is an amenable number.

351013540433 is a deficient number, since it is larger than the sum of its proper divisors (2324593135).

351013540433 is a wasteful number, since it uses less digits than its factorization.

351013540433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2324593134.

The product of its (nonzero) digits is 32400, while the sum is 32.

Adding to 351013540433 its reverse (334045310153), we get a palindrome (685058850586).

The spelling of 351013540433 in words is "three hundred fifty-one billion, thirteen million, five hundred forty thousand, four hundred thirty-three".