35113420450113 has 4 divisors (see below), whose sum is σ = 46817893933488. Its totient is φ = 23408946966740.

The previous prime is 35113420450049. The next prime is 35113420450117. The reversal of 35113420450113 is 31105402431153.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 35113420450113 - 2⁶ = 35113420450049 is a prime.

It is a super-3 number, since 3×35113420450113³ (a number of 42 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (35113420450117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5852236741683 + ... + 5852236741688.

It is an arithmetic number, because the mean of its divisors is an integer number (11704473483372).

Almost surely, 2^{35113420450113} is an apocalyptic number.

It is an amenable number.

35113420450113 is a deficient number, since it is larger than the sum of its proper divisors (11704473483375).

35113420450113 is a wasteful number, since it uses less digits than its factorization.

35113420450113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11704473483374.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 35113420450113 its reverse (31105402431153), we get a palindrome (66218822881266).

The spelling of 35113420450113 in words is "thirty-five trillion, one hundred thirteen billion, four hundred twenty million, four hundred fifty thousand, one hundred thirteen".