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351144343120147 is a prime number
BaseRepresentation
bin100111111010111010010100…
…1110101100010100100010011
31201001022001221000120112000221
41033311310221311202210103
5332011122103314321042
63242453252334053511
7133651225111224343
oct11765645165424423
91631261830515027
10351144343120147
11a1981530417035
123347216204a297
13120c1a006c1895
14629d696824d23
152a8e10bda6d67
hex13f5d29d62913

351144343120147 has 2 divisors, whose sum is σ = 351144343120148. Its totient is φ = 351144343120146.

The previous prime is 351144343120073. The next prime is 351144343120163. The reversal of 351144343120147 is 741021343441153.

It is a strong prime.

It is an emirp because it is prime and its reverse (741021343441153) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 351144343120147 - 215 = 351144343087379 is a prime.

It is not a weakly prime, because it can be changed into another prime (351144343420147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175572171560073 + 175572171560074.

It is an arithmetic number, because the mean of its divisors is an integer number (175572171560074).

Almost surely, 2351144343120147 is an apocalyptic number.

351144343120147 is a deficient number, since it is larger than the sum of its proper divisors (1).

351144343120147 is an equidigital number, since it uses as much as digits as its factorization.

351144343120147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 43.

The spelling of 351144343120147 in words is "three hundred fifty-one trillion, one hundred forty-four billion, three hundred forty-three million, one hundred twenty thousand, one hundred forty-seven".