Base | Representation |
---|---|
bin | 100000101101001001… |
… | …000111101111111011 |
3 | 10100122101000201121001 |
4 | 200231021013233323 |
5 | 1033404434312443 |
6 | 24044345225431 |
7 | 2352143313523 |
oct | 405511075773 |
9 | 110571021531 |
10 | 35117104123 |
11 | 13990765102 |
12 | 6980792277 |
13 | 340857576a |
14 | 19b1cb0683 |
15 | da7eb2d4d |
hex | 82d247bfb |
35117104123 has 2 divisors, whose sum is σ = 35117104124. Its totient is φ = 35117104122.
The previous prime is 35117104117. The next prime is 35117104147. The reversal of 35117104123 is 32140171153.
It is a weak prime.
It is an emirp because it is prime and its reverse (32140171153) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35117104123 - 29 = 35117103611 is a prime.
It is a super-2 number, since 2×351171041232 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 35117104091 and 35117104100.
It is not a weakly prime, because it can be changed into another prime (35117104523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17558552061 + 17558552062.
It is an arithmetic number, because the mean of its divisors is an integer number (17558552062).
Almost surely, 235117104123 is an apocalyptic number.
35117104123 is a deficient number, since it is larger than the sum of its proper divisors (1).
35117104123 is an equidigital number, since it uses as much as digits as its factorization.
35117104123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 35117104123 its reverse (32140171153), we get a palindrome (67257275276).
The spelling of 35117104123 in words is "thirty-five billion, one hundred seventeen million, one hundred four thousand, one hundred twenty-three".
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