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351300668073 = 3117100222691
BaseRepresentation
bin1010001110010110010…
…01101100101010101001
31020120202202011222112120
411013023021230222221
521223430432334243
6425215120301453
734244362260315
oct5071311545251
91216682158476
10351300668073
11125a93083543
1258101a71889
13271871ab6c4
14130084c8b45
159211326c83
hex51cb26caa9

351300668073 has 4 divisors (see below), whose sum is σ = 468400890768. Its totient is φ = 234200445380.

The previous prime is 351300668039. The next prime is 351300668099. The reversal of 351300668073 is 370866003153.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 351300668073 - 216 = 351300602537 is a prime.

It is a super-2 number, since 2×3513006680732 (a number of 24 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (351300268073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58550111343 + ... + 58550111348.

It is an arithmetic number, because the mean of its divisors is an integer number (117100222692).

Almost surely, 2351300668073 is an apocalyptic number.

It is an amenable number.

351300668073 is a deficient number, since it is larger than the sum of its proper divisors (117100222695).

351300668073 is a wasteful number, since it uses less digits than its factorization.

351300668073 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117100222694.

The product of its (nonzero) digits is 272160, while the sum is 42.

The spelling of 351300668073 in words is "three hundred fifty-one billion, three hundred million, six hundred sixty-eight thousand, seventy-three".

Divisors: 1 3 117100222691 351300668073