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35135445432001 is a prime number
BaseRepresentation
bin1111111110100100110111…
…01111100111011011000001
311121101220201121021201220211
413333102123233213123001
514101124343012311001
6202421000101234121
710254311043335635
oct777223357473301
9147356647251824
1035135445432001
1110216949a70372
123b35599702941
13167b3485c4345
148967c94ccdc5
1540de48450351
hex1ff49bbe76c1

35135445432001 has 2 divisors, whose sum is σ = 35135445432002. Its totient is φ = 35135445432000.

The previous prime is 35135445431963. The next prime is 35135445432007. The reversal of 35135445432001 is 10023454453153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19626459390976 + 15508986041025 = 4430176^2 + 3938145^2 .

It is a cyclic number.

It is not a de Polignac number, because 35135445432001 - 213 = 35135445423809 is a prime.

It is not a weakly prime, because it can be changed into another prime (35135445432007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17567722716000 + 17567722716001.

It is an arithmetic number, because the mean of its divisors is an integer number (17567722716001).

Almost surely, 235135445432001 is an apocalyptic number.

It is an amenable number.

35135445432001 is a deficient number, since it is larger than the sum of its proper divisors (1).

35135445432001 is an equidigital number, since it uses as much as digits as its factorization.

35135445432001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432000, while the sum is 40.

Adding to 35135445432001 its reverse (10023454453153), we get a palindrome (45158899885154).

The spelling of 35135445432001 in words is "thirty-five trillion, one hundred thirty-five billion, four hundred forty-five million, four hundred thirty-two thousand, one".