Base | Representation |
---|---|
bin | 100000101110100010… |
… | …100001101111111001 |
3 | 10100201000010110112120 |
4 | 200232202201233321 |
5 | 1033431434311213 |
6 | 24050543431453 |
7 | 2352546450054 |
oct | 405642415771 |
9 | 110630113476 |
10 | 35140541433 |
11 | 139a2a12988 |
12 | 69885b5589 |
13 | 34103905aa |
14 | 19b5051a9b |
15 | daa092423 |
hex | 82e8a1bf9 |
35140541433 has 4 divisors (see below), whose sum is σ = 46854055248. Its totient is φ = 23427027620.
The previous prime is 35140541417. The next prime is 35140541437. The reversal of 35140541433 is 33414504153.
35140541433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 35140541433 - 24 = 35140541417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 35140541394 and 35140541403.
It is not an unprimeable number, because it can be changed into a prime (35140541437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5856756903 + ... + 5856756908.
It is an arithmetic number, because the mean of its divisors is an integer number (11713513812).
Almost surely, 235140541433 is an apocalyptic number.
It is an amenable number.
35140541433 is a deficient number, since it is larger than the sum of its proper divisors (11713513815).
35140541433 is a wasteful number, since it uses less digits than its factorization.
35140541433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11713513814.
The product of its (nonzero) digits is 43200, while the sum is 33.
The spelling of 35140541433 in words is "thirty-five billion, one hundred forty million, five hundred forty-one thousand, four hundred thirty-three".
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