Base | Representation |
---|---|
bin | 10000000010000000000101… |
… | …11010110011100001101001 |
3 | 11121211011111222101110200112 |
4 | 20001000002322303201221 |
5 | 14110041412434113101 |
6 | 202551022535544105 |
7 | 10265645454244115 |
oct | 1001000272634151 |
9 | 147734458343615 |
10 | 35253140535401 |
11 | 1026185586a568 |
12 | 3b5436552b035 |
13 | 1689484110869 |
14 | 89c392690745 |
15 | 412035db86bb |
hex | 201002eb3869 |
35253140535401 has 4 divisors (see below), whose sum is σ = 35253852094032. Its totient is φ = 35252428976772.
The previous prime is 35253140535391. The next prime is 35253140535421. The reversal of 35253140535401 is 10453504135253.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 35253140535401 - 214 = 35253140519017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (35253140535421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355704995 + ... + 355804088.
It is an arithmetic number, because the mean of its divisors is an integer number (8813463023508).
Almost surely, 235253140535401 is an apocalyptic number.
It is an amenable number.
35253140535401 is a deficient number, since it is larger than the sum of its proper divisors (711558631).
35253140535401 is an equidigital number, since it uses as much as digits as its factorization.
35253140535401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 711558630.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 35253140535401 in words is "thirty-five trillion, two hundred fifty-three billion, one hundred forty million, five hundred thirty-five thousand, four hundred one".
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